Question

in reaction , CU(s) +H2(g) =Cu(s) +H2o (l) ​

Answer 1

Answer:

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In this reaction hydrogen gains oxygen and forms water, hence it is oxidised. On the other hand copper oxide loses oxygen and hence reduced.

Answer 2

Answer:

CuO(s) + $H_{2}$ (g) → Cu(s) + $H_{2}$O(l)

In this reaction hydrogen gains oxygen and forms water, hence it is oxidised. On the other hand copper oxide loses oxygen and hence reduced

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