Question

In reaction n2o4(g)⇌2no2(g) what will be the value of kc

Answer 1

Answer:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Explanation:

We are given an equilibrium reaction

$N_2O_4\rightleftharpoons 2 NO_2$

We have to find the equilibrium constant for the reaction

We know that

aA\rightleftharpoons  bB

Then , $K_c=\frac{[B]^b}{[A]^a}$

Therefore, using this formula we get

$k_c=\frac{[NO_2]^2}{[N_2O_4]}$

Hence, the equilibrium constant =$K_c=\frac{[NO_2]^2}{[N_2O_4]}$