in rectangle ABCD AC=29and CD=21. find the perimeter of the rectangle?
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100 is the answer check it
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In rectangle ABCD
AC = 29 cm
CD = AB = 21 cm
Then In right ΔABC
By Pythagoras theorem,
AC² = AB² + BC²
BC² = AC² - AB²
BC² = (29)² - (21)²
BC² = 841 - 441
BC = √400
BC = 20 cm (taking Positive Root)
Perimeter of Rectangle ABCD = 2(AB+BC)
= 2(21+20)
= 2(41)
= 82 cm
:) Hope This Helps!!!
AC = 29 cm
CD = AB = 21 cm
Then In right ΔABC
By Pythagoras theorem,
AC² = AB² + BC²
BC² = AC² - AB²
BC² = (29)² - (21)²
BC² = 841 - 441
BC = √400
BC = 20 cm (taking Positive Root)
Perimeter of Rectangle ABCD = 2(AB+BC)
= 2(21+20)
= 2(41)
= 82 cm
:) Hope This Helps!!!
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nitthesh7:
if it helps u a lot pls mark it as brainliesy=t
sry brainliest
but the answer is 84
no ive checked 82 is the correct ans
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