Question

In rectangle ABCD ,prove that âACB =~âCAD

Answer 1

given -ABCD is a rectangle

to prove -angle ACB =~DAC

proof-in triangle DAC and triangle ACB

                         AC =AC(COMMON)

                         ANGLE ADC= ANGLE ABC(EACH 90)

                        ANGLE DAC = ACB (ALTERNATIVE INTERIOR ANGLE)

                         SO TRIANGLE DAC =~TO TRIANGLE ACB (BY ASA CONGRENCY RULE)