In remainder theorem, on dividing a polynomial p(x) by x-a, the remainder will be p(a). Why do we substitute x as a ?
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Here p(x) is the polynomial and it is divided by x-a.
In order to find x from the polynomial;
x-a = 0
x = a.
So in the place of x we substitute a.
*If f(x) is divided by x-2 then the remainder is f(2)
bcoz x-2 = 0
x = 2. That's how we do it........
In order to find x from the polynomial;
x-a = 0
x = a.
So in the place of x we substitute a.
*If f(x) is divided by x-2 then the remainder is f(2)
bcoz x-2 = 0
x = 2. That's how we do it........
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