Question

in resonance tube, two successive positions of resonance are obtained at 15 cm and 48 cm. if the frequency of the fork is 500 cps, the velocity of the sound is

Answer 1

In resonance tube

Wavelength= 2(L2 - L1)

Wavelength= 2(48-15)= 66 cm

Velocity = 66/100 × 500 = 330m/s

Answer 2

Given:

In resonance tube

$L_1=15 cm,L_2=48 cm$

Frequency, f=500 cps

To find:

Velocity of the sound

Solution:

For resonance tube

$\lambda=2(L_2-L_1)$

Using the formula

$\lambda=2(48-15)=66 cm$

1 m=100 cm

Therefore,

$66 cm=\frac{66}{100}m=0.66 m$

$\lambda=0.66 m$

Velocity, v=$f\times\lambda$

Using the formula

$v=0.66\times 500=330 m/s$

Hence, the velocity of sound=330 m/s