Question

in rhombus ab=bc=cd=da=? of ac=12cm and=16cm​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Find the perimeter and area of the quadrilateral ABCD in which AB = 17 cm, AD = 9 cm, CD = 12 cm, ∠ACB = 90° and AC = 15 cm.Since ∆ACB is right angled at C, we have

AC = 15 cm; AB = 17 cm

AB2 = AC2 + BC2

 

Area of right angled triangle ABC, say A1 is given by

, where,

Base = BC = 8 cm; Height = AC = 15 cm



Area of triangle ADC, say A2 having sides a, b, c and s as semi-perimeter is given by

, where

a = AD = 9 cm; b = DC = 12 cm; c = AC = 15 cm 





Area of quadrilateral ABCD, say A

A = Area of ∆ACB + Area of ∆ADC





Perimeter of quadrilateral ABCD, say P