Question

in rhombus ABCD angel A = 3x+20 , angel C = x+30 then find angle B​

Answer 1

ABCD IS A RHOMBUS.

So,opposite angles are equal

So, in this quadilateral..

[<A=<C ] and [<B=<D] are oppsite angles

So,

<A=<C

or,

(3x+20°)=(x+30°)[ Putting the values of <A and <C]

࿇Equating:-

2x=10°

$x = \frac{10}{2}$

.•. x=5°

.•. <C=5°+30°

=》<C=35°
<C+<B=180°
=》<B=180°-35°
=》<B=145°
Hence this is your answer

Answer 2

ABCD IS A QUADILATERAL.

So, in this quadilateral..

[<A, <C ] and [<B,<D] are oppsite angles are equal

So,

<A+<C=180°

or,

(3x+20°)+(x+30°)=180°[ Putting the values of <A and <C]

࿇Equating:-

4x+50°=1

4x=130°

x = \frac{180}{40}x=

40

180

x=4.5

<C=4.5°+30°

=》<C=34.5°

<C+<B=180°

=》<B=180°-34.5°

=》<B=145.5°

Hence this is your answer