Question

In rhombus ABCD, (angle)ABC=72°. Find (angle) ACD​

Answer 1

Answer:

72+72+72

216

Step-by-step explanation:

216 is the answer because in rhombus all sides are equal

Answer 2

The value of angle ACD is 72°

Step-by-step explanation:

Gievn that $\angle ABC = 72^\circ$

$\angle ABC = \angle ADC = 72^\circ$'

(opposite angles of rhombus are equal )

since , we know that all the sides of rhombus are equal

therefore in triangle ADC , ADC is an isosceles triangle

now , in triangle ADC

AD =CD

$\angle CAD = \angle ACD$

(angle opposite to equal sides are equal )

therefore

$\angle ADC +\angle CAD + \angle ACD = 180^\circ$ (angle sum property)

$72+ \angle ACD + \angle ACD = 180\\\\2\angle ACD = 180-72 \\\\2\angle ACD =108\\\\\angle ACD =54^\circ$

hence , The value of angle ACD is 72°

#Learn more:

ABCD is a rhombus with angle ABC=128° Find angle ACD

https://brainly.in/question/7940084