in rhombus ABCD, <A=<B-30°,then find <c give method
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In rhombus ABCD , angle A= 3x+ 20 , angle C =x + 30
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SEE THE ATTACHMENT FOR THE FIGURE
AS ABCD IS A RHOMBUS
ANGLE A=ANGLE C
ANGLE D=ANGLE B
GIVEN
ANGLE A=ANGLE B-30°
AND AS WE KNOW RHOMBUS IS A QUADRILATERAL THE SUM OF ALL ANGLES WILL BE EQUAL TO 360°
ANGLE A
+ ANGLE B+ANGLE C +ANGLED=360°
AS WE KNOW
ANGLE C=ANGLE A
ANGLE C= ANGLE B -30°
AND ANGLE D=ANGLE B
SO
ANGLE A+ANGLE B +ANGLE C +ANGLE D= 360°
ANGLE B-30° +ANGLE B + ANGLE B-30°+ANGLE B=360°
4(ANGLE B)-60°=360°
ANGLE B=420°/4
ANGLE B=105°
SO
ANGLE C=ANGLE B-30°
ANGLE C=105°-30°
=75°
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