Question

In right A ABC, right angled at C, AB = 10 units, BC = 8 units and z ABC = e.

Verify the identities

(1) cosec?0 cot2e = 1 =

(ii) 1 + tane = seco​

Answer 1

Answer:  draw a tri. ABC rt. angled at C.

by Pythagoras theorem

AB2= AC2 + BC2

=) AC2 = AB2 - BC2

=)AC2=100-64

=)AC=6.

now cosec2=(AB/AC)2=100/36

cot2=(BC/AC)2=64/36

substituting the values

=) 100-64/36 = 36/36 =1

hence proved

now tan2 =(AC/BC)2 =36/64

substituting the values we get

1+ 36/64 =64+36/64 = 100/64

therfore sec2 = 100/64                                                                                                                                                   [ since sec2 =(AB/BC)2 =100/64]

hence proved..

Q.E.D.

Hope u wud admire this solution

Answer 2

Step-by-step explanation:

draw a tri. ABC rt. angled at C.

by Pythagoras theorem

AB2= AC2 + BC2

=) AC2 = AB2 - BC2

=)AC2=100-64

=)AC=6.

now cosec2=(AB/AC)2=100/36

cot2=(BC/AC)2=64/36

substituting the values

=) 100-64/36 = 36/36 =1

hence proved

now tan2 =(AC/BC)2 =36/64

substituting the values we get

1+ 36/64 =64+36/64 = 100/64

therfore sec2 = 100/64                                                                                                                                                   [ since sec2 =(AB/BC)2 =100/64]

hence proved.

You can trust me, i have done this question multiple times.