Question

In Right angle tiangle the length of the perpendicular side are 15cm and 18cm find the length of it's hypotenus

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Answer 1

Answer:

In a right angled triangle square of hypotenuse is equal to the sum of square of the perpendicular sides

Square of hypotenuse = Square of one side+ Square of other side

=(15)² +(18)²

=225+324

Square of hypotenuse=549

Hypotenuse. = Under root 549

=23.4

Answer 2

Answer:

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\linethickness{0.7mm}\qbezier(1, 0)(1,0)( 1,3)\qbezier(5,0)(5, 0)(1.075,3)\qbezier(5,0)(1,0)(1,0)\put(1.4,0){\line(0,3){0.3}}\put(1,0.3){\line(1,0){0.4}}\put(-0.3,1.5){15 cm}\put(0.6,-0.2){ \sf B } \put(0.6,3){ \sf A }\put(2.3,-0.3){18 cm}\put(5.1, - 0.2){ \sf C }\end{picture}$

Let ∆ ABC be the right angle triangle, right angled at B.

By Phythagoras theorem we get :

➝ AC² = AB² + BC²

➝ (AC)² = (15)² + (18)²

➝ AC² = 225 + 324

➝ AC² = 549

➝ AC = 23.4 cm