Question

In right angle Triangle,AB=BC.Then Angle A is equal to​

Answer 1

$\huge\fcolorbox{black}{pink}{Solution}$

$\rightarrow$ Given-A right angle triangle with sides AC=BC

$\rightarrow$ Now to find-Angle A

$\huge\textsf{Proof}$

In a right angle triangle where AB=BC ,angle A= angle C (due to reason that angle opposite to equal sides are also equal)

Here angle B=90° (since it is a right angled triangle)

$\rightarrow$ Now, $\angle\:A$ + $\angle\:B$ + $\angle\:C$ = 180° {Angle Sum Property}

$\rightarrow$ $\angle\:A$ + $\angle\:C$ = 180° - $\angle\:B$

$\rightarrow$$\angle\:A$ + $\angle\:C$ = 180° - 90°

$\rightarrow$$\angle\:A$ + $\angle\:A$ = 90° {since Angle A = Angle C}

$\rightarrow$ 2 $\angle\:A$ = 90°

$\rightarrow$ $\angle\:A$ = $\dfrac{90°}{2}$

$\rightarrow$$\angle\:A$ = 45 °

$\Huge{\red{\underline{\textsf{Angle\:A=45°}}}}$

Answer 2

then angle A will be 45

as the triangle is isosceles

angle A +angle B = 90°

I hope this will surely help u mate