Question

In right angle triangle ABC, 8 cm, 15 cm and 17 cm are the lengths of AB, BC and
respectively. Then, find out sin A, cos A and tan A.

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Answer 1

Answer:

GIVEN :-

• In right angle triangle ABC, 8 cm, 15 cm and 17 cm are the lengths of AB, BC

TO FIND :-

• find out sin A, cos A and tan A.

SOLUTION :-

AB = 8 cm, BC = 15 cm, AC = 17 cm

According to the diagram,

AB = Adjacent Side, BC = Opposite Side, AC = Hypotenuse.

Sin A = Opposite / Hypotenuseu

➡️ Sin A = BC / AC

➡️ Sin A = 15 / 17

Cos A = Adjacent / Hypotenuse

➡️ Cos A = AB / AC

➡️ Cos A = 8 / 17

Tan A = Opposite / Adjacent

➡️ Tan A = BC / AB

➡️ Tan A = 15 / 8

Answer 2

AB = 8 cm

AB = 8 cmBC = 15 cm

AB = 8 cmBC = 15 cmAC = 17 cm

According to the diagram,

AB = Adjacent Side

AB = Adjacent SideBC = Opposite Side

AB = Adjacent SideBC = Opposite SideAC = Hypotenuse.

Now we need to find Sin A, Cos A, and Tan A.

Let us calculate Sin A first,

Sin A = Opposite / Hypotenuse

=> Sin A = BC / AC

=> Sin A = 15 / 17

Cos A = Adjacent / Hypotenuse

=> Cos A = AB / AC

=> Cos A = 8 / 17

Tan A = Opposite / Adjacent

=> Tan A = BC / AB

=> Tan A = 15 / 8

The answer is Tan A = 15 / 8

Hence Verified ✓

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