In right angle triangle ABC, 8 cm, 15 cm and 17 cm are the lengths of AB, BC and
respectively. Then, find out sin A, cos A and tan A.
מתן
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Answers
Answer:
GIVEN :-
- In right angle triangle ABC, 8 cm, 15 cm and 17 cm are the lengths of AB, BC
TO FIND :-
- find out sin A, cos A and tan A.
SOLUTION :-
AB = 8 cm, BC = 15 cm, AC = 17 cm
According to the diagram,
AB = Adjacent Side, BC = Opposite Side, AC = Hypotenuse.
Sin A = Opposite / Hypotenuseu
➡️ Sin A = BC / AC
➡️ Sin A = 15 / 17
Cos A = Adjacent / Hypotenuse
➡️ Cos A = AB / AC
➡️ Cos A = 8 / 17
Tan A = Opposite / Adjacent
➡️ Tan A = BC / AB
➡️ Tan A = 15 / 8
AB = 8 cm
AB = 8 cmBC = 15 cm
AB = 8 cmBC = 15 cmAC = 17 cm
According to the diagram,
AB = Adjacent Side
AB = Adjacent SideBC = Opposite Side
AB = Adjacent SideBC = Opposite SideAC = Hypotenuse.
Now we need to find Sin A, Cos A, and Tan A.
Let us calculate Sin A first,
Sin A = Opposite / Hypotenuse
=> Sin A = BC / AC
=> Sin A = 15 / 17
Cos A = Adjacent / Hypotenuse
=> Cos A = AB / AC
=> Cos A = 8 / 17
Tan A = Opposite / Adjacent
=> Tan A = BC / AB
=> Tan A = 15 / 8
The answer is Tan A = 15 / 8
Hence Verified ✓
