Question

In right angle triangle ABC, 8 CM, 15 cm and 17 cm are the lengths of AB, BC and CA respectively. Then, sin A,cos A and tan A. ​

Answer 1

First draw a triangle ABC, let AB be height, and BC be base and CA be hypotenuse

For Sin A BC will be opp and AC will be hypotenuse, so

1.) Sin A= opp/hyp= 15/17

For Cos A AB is adjacent and AC is hypotenuse

2.) Cos A= adj/hyp=8/17

For Tan A we want only opp and adj so BC is opp and AB is adj, so

3.) Tan A= opp/adj=15/8

hence proved

Answer 2



Solution:-

In ∆ ABC

• AB = 8 cm.

• CA = 15 cm.

• CA = 17 cm.

In Right ∆ :-

• Hypotenuse is the longest sides .

• Hypotenuse = CA = 17 cm

• \_B = 90°

 

$\begin{gathered}\begin{gathered}\begin{gathered} \: \: \: \: \: \: \begin{gathered}\boxed {\begin{array}{cc} \\ \\ \bullet \rm \: Sin \: a = \frac{Opposite \: side}{Hypotenuse} = \frac{15}{17} \: cm \\ \\ \bullet \rm \: Cos \: a = \frac{Opposite \: side}{Hypotenuse} = \frac{8}{12} \: cm \\ \\ \bullet\rm \: Tan \: A = \frac{Opposite \: Side}{Adjacent \: Side} \: = \frac{15}{8} \: cm\end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

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@Shivam