In right angle triangle ABC, 8 cm, 15 cm and 17 cm are the lengths of AB, BC and CA
respectively. Then, find sin A, cos A and tan A.
Answers
Answer:
hope this will help you
Explanation:
AB = 8 cm, BC = 15 cm, AC = 17 cm
According to the diagram,
AB = Adjacent Side, BC = Opposite Side, AC = Hypotenuse.
Now we need to find Sin A, Cos A, and Tan A.
Let us calculate Sin A first,
Sin A = Opposite / Hypotenuse
=> Sin A = BC / AC
=> Sin A = 15 / 17
Cos A = Adjacent / Hypotenuse
=> Cos A = AB / AC
=> Cos A = 8 / 17
Tan A = Opposite / Adjacent
=> Tan A = BC / AB
=> Tan A = 15 / 8
Explanation:
According to question,
Angle B =90
0
for angleA
base(B)=8cm
perpendicular(P)=15cm
hypotensue(H)= 17cm
sinA= H
P
= 17
15
cosA= H
B
= 17
8
tanA= B
P
= 8
15