in right angle triangle abc angle C is equal to 90 degree angle A is equal to 30 degree and AB is equal to 10 cm then find the value of AC?
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Step-by-step explanation:
Since AB=AC,
So, △ABC is Right-angled isosceles.
∠B=∠C ...(angles opp. to equal sides are equal)
∠A+∠B+∠C=180∘ ...(angle - sum property of a triangle)
Substituting ∠B=∠C, ∠A=90o
90∘+2∠B=180∘
2∠B=180∘–90∘=90∘
⇒∠B=45∘
So, ∠C=∠B=45o.
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