Question

In right angle triangle ABC right angled at C, in which AB=13cm, BC=5cm, than find cos sqauar B+ sin sqauar A

Answer 1

Answer:

cos2B+Sin2A=1

Step-by-step explanation:

First we'll find the perpendicular by Pythagoras theorem

(AB)2=(BC)2+(AC)2

(13)2=(5)2+(AC)2

169=25+AC2

169-25=AC2

144=AC2

12=AC

As we need to find,

cos2B+sin2A

CosA=Base/Height

SinA=Perpendicular/Height

(5/13)2+(12/13)2

25/169+144/169

169/169=1 (Answer)