Question

in right angle triangle ABC the length of the legs are given find the length of hypotenuse (i) A = 6cm B=4 CM
(ii) a =8cm b=15 CM (iii) a =3cm b =4 cm
(iv) a= 2cm, b=1.5cm​

Answer 1

ANSWER

$Using Pythagoras theorem in △ABC</p><p>(AB) </p><p>2</p><p> +(BC) </p><p>2</p><p> =(AC) </p><p>2</p><p> </p><p>(15) </p><p>2</p><p> +(8) </p><p>2</p><p> =(AC) </p><p>2</p><p> </p><p>⇒(AC) </p><p>2</p><p> =225+64=289</p><p>⇒AC=17cm</p><p></p><p>Now inradius r= </p><p>s</p><p>Δ</p><p> </p><p> </p><p></p><p>where Δ is the area of triangle and s is semi perimeter.</p><p></p><p>Δ= </p><p>2</p><p>1</p><p> </p><p> ×8×15=60</p><p></p><p>s= </p><p>2</p><p>8+15+17</p><p> </p><p> = </p><p>2</p><p>40</p><p> </p><p> =20</p><p>⇒r= </p><p>s</p><p>Δ</p><p> </p><p> = </p><p>20</p><p>60</p><p> </p><p> =3cm$

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Answer 2

Step-by-step explanation:

1. 2√13

2. 3√29

3. 5

4.5√17