Question

In right angle triangle PQR, right angle is at Q and PQ=6cms angle rpq=60 determine the length of QR and PR.

Answer 1

Answer:

6root3 & 12

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$\tan( theta) = \frac{p}{3} = \tan(60) = \frac{rq}{qp}$

$\sqrt{3} = \frac{rq}{6}$

$q = 6 \sqrt{3}$

$\sin(theta) = \frac{rr}{rp}$

$\frac{ \sqrt{3} }{2} = \frac{rq}{rp}$

$rp = \frac{2}{ \sqrt{3} } = \times rq$

$= \frac{2}{ \sqrt{3} } \times 6 \sqrt{3}$

$\sqrt{3} and \sqrt{3} cancel$

$2 \times 6 = 12$