In right angle triangle ΔPQR, right angle is at Q and PQ = 6cms ∠RPQ = 60°. Determine the lengths of QR and PR.
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QR=6*3^0.5cm PQ=12cm
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Answer:
PR = 12 cm
QR = 6 √3 cm
Step-by-step explanation:
PQR, right angle is at Q
PQ = Base = 6
QR = Height
PR = Hypotenuse
Cos ∠RPQ = Base / Hypotenuse
=> Cos 60° = PQ / PR
=> (1/2) = 6/PR
=> PR = 12 cm
PR² = PQ² + QR²
=> 12² = 6² + QR²
=> QR² = 144 - 36
=> QR² = 108
=> QR² = 36 * 3
=> QR = 6 √3 cm
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