In right angled triangle the hypotenuse is 10cm more than the shorter side.if third side is 6cm less than hypotenuse,find the sides of right angled triangle
Answers
Answer:
Step-by-step explanation:
Given In right angled triangle the hypotenuse is 10 cm more than the shorter side.if third side is 6 cm less than hypotenuse,find the sides of right angled triangle
Let the length of shorter side be x cm
Now length of hypotenuse is 10 cm more than x, so it will be x + 10 cm
Given length of third side is 6 cm less than hypotenuse , so it will be x + 10 - 6 = x + 4 cm
We know that Pythagoras theorem states that the square on the hypotenuse is equal to the sum of the squares on the other two sides.
So (x + 10)^2 = x^2 + (x + 14)^2
We get x^2 - 12 x - 84 = 0
We know x = - b ± √b^2 - 4 ac / 2 a
x = 12 ± √144 + 336 / 2
x = 16.9 cm
So we get shorter side as 16 .9 cm
Now hypotenuse = x + 10 = 16.9 + 10 = 26.9 cm
and third side = x + 4 = 16.9 + 4 = 20.9 cm
So sides are 16.9 cm, 26.9 cm and 20.9 cm
Answer:
Shorter side = 16.955 cm
Third side = 20.955 cm
hypotenuse = 26.955 cm
Step-by-step explanation:
In right angled triangle the hypotenuse is 10cm more than the shorter side.if third side is 6cm less than hypotenuse,find the sides of right angled triangle
Let say shorter Side = x cm
Hypotenuse = x + 10 cm
Third Side = hypotenuse - 6 cm = x + 10 - 6 = x + 4 cm
in right angle triangle applying Pythagoras theorem
hypotenuse² = Base² + height²
(x+10)² = x² + (x+4)²
=> x² + 100 + 20x = x² + x² + 16 + 8x
=> x² -12x - 84 = 0
=> x = (12 ± √(144 + 336) )/2
=> x = (12 ± 21.91)/2
=> x = 16.955 as x can not be negative
Shorter side = 16.955 cm
Third side = 20.955 cm
hypotenuse = 26.955 cm