Question

in right angled tringle ABC , <A =90° , BC = 10 cm , AB = 6 cm , than find AC​

Answer 1

$\bigstar\textrm{ Since ABC is a right angled triangle and \angle A = 90 ^\circ , So Hypotenuse is BC }$

$\longrightarrow\rm{BC^2=AB^2+AC^2\quad...\:From\:Pythagoras\:Theorem}$

$\longrightarrow\rm{(10\:cm)^2=(6\:cm)^2+AC^2}\longrightarrow\rm{100\:cm^2=36\:cm^2+AC^2}$

$\longrightarrow\rm{AC^2=100\:cm^2-36\:cm^2=64\:cm^2}\longrightarrow\rm{AC=\sqrt{64\:cm^2}=8\:cm}$

Answer 2

Step-by-step explanation:

AC=√10^2-6^2=√100-36

=√64=8

AC=8cm