Question

In right triangle ABC right angled at B, sinA = 5/13 find tan A

Answer 1

Sin a=5/13

Sin a=bc/ac

Thus

Bc=5 and ac=13

Using Pythagoras theorem

13^2=5^2+ab^2

169=25+ab^2

ab^2=144

ab=12cm

Now, tan a=bc/ab

Tan a=5/12

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Answer 2

Answer:

5/12

Step-by-step explanation: