Question

In right triangle PQR, angel P =90°, PQ=6cm and RP =8cm , then find the value of cos R and cos Q ​

Answer 1

Answer:It is given that

PQ=8cm and QR=6cm

∠PQR=90  

∘

 

Using Pythagoras Theorem

PR  

2

=PQ  

2

+QR  

2

 

Substituting the values

PR  

2

=8  

2

+6  

2

 

By further calculation

PR  

2

=64+36=100

PR=√100

So we get

PR=10cm

solution