Question

In root xsqure-5x+22+ in root xsqure -5x+6 =4 find the value of x

Answer 1

Answer:

Here is ur answer

Step-by-step explanation:

√x2-5x+22 +√x2-5x+6 = 4

x2-5x+22 + x2-5x+6=2 ....taking Square root on both sides

2x2-10x+28=2

2x2-10x+26=0

2x2-10x= -26

Now,Third term =( 1/2 * coefficient of x)`2

: 1/2 * -10)2

T,t = 25

now add 25 on both side of above equation

2x2 -10x +25 = -26+25