Question

IN SHM THE MASS OF PARTICLE IS M AND THE ANGULAR FREQUENCY IS OMEGA. then the force constant of shm will be​

Answer 1

Answer:

Given:

Mass = m

Angular freq. = ω

To find:

Force constant of SHM.

Calculation:

We know the following relationship :

$Time \: period = \frac{2\pi}{ \omega} = 2\pi \sqrt{ \frac{m}{k} }$

So, we can say that :

$\omega = \sqrt{ \frac{k}{m} }$

$= > { \omega}^{2} = \frac{k}{m}$

$= > k = { \omega \times m}^{2}$

So final answer is:

$\boxed {force \: const. = { \omega}^{2} \times m}$

Answer 2

Heya!

$\color{red}{good\: question}$

✔Refer to the attachment please✔