In sin A = 9/41,find the values of cosA and tanA
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SinA=9/41
so cosA=√1-(SinA)^2
=√1-(9/41)^2
=√1-(81/1681)
=√(1681-81)/1681
=√1600/1681
=40/41
TanA.=SinA/CosA=(9/41)*(41/40)
=9/40
so cosA=√1-(SinA)^2
=√1-(9/41)^2
=√1-(81/1681)
=√(1681-81)/1681
=√1600/1681
=40/41
TanA.=SinA/CosA=(9/41)*(41/40)
=9/40
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