In so2 the mass of sulphur in combination with 3.0 g of oxygen is
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Answered by
24
Here is your answer,
In SO2
32g of S contains 32g of O2,
Therefore,
for 3g of O2 will have X grams of suplhur
SO2 O2
X -----------------> 3g
32g --------------> 32g
Therefore by cross multiply,
X = 3 x 32/32
X = 3g of Suplhur
Therefore for 3g of oxygen it contains 3g of Sulphur.
I hope this might have helped you.
In SO2
32g of S contains 32g of O2,
Therefore,
for 3g of O2 will have X grams of suplhur
SO2 O2
X -----------------> 3g
32g --------------> 32g
Therefore by cross multiply,
X = 3 x 32/32
X = 3g of Suplhur
Therefore for 3g of oxygen it contains 3g of Sulphur.
I hope this might have helped you.
Answered by
3
Answer:
3g of sulphur
Explanation:
X = 3g
32g = 32g
Cross multiplication
32x = 32(3)
x = 32(3)/32
x = 96/32
x = 3g
So, sulphur in So2 is 3g
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