in solving AP ..if we have to find multiples of 7 between 500 and 900.. how will we do.. i mean i need to check one by one ..or is there any trick??
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a (first term of series,should be multiple of 7 greater and nearest to 500) = 504
l(last term of series,should be multiple of 7 ,smaller and nearest than 900) = 896
d(common difference)=7
l= a+(n-1)d
896=504+(n-1)7
896-504=7n-7
392+7=7n
399=7n
n=57
Hence
Number of multiples of 7 between 500 and 900 are 57
l(last term of series,should be multiple of 7 ,smaller and nearest than 900) = 896
d(common difference)=7
l= a+(n-1)d
896=504+(n-1)7
896-504=7n-7
392+7=7n
399=7n
n=57
Hence
Number of multiples of 7 between 500 and 900 are 57
Answered by
1
Answer:
there are 57 multiples of 7 between 500 and 900
Step-by-step explanation:
formula used -> an = a +(n-1)d
here an = 896 (it is the last term lesser than 900 divisible by 7)
and a = 504 (which is the first term divisible by 7 grater than 500)
and d = 7 (since we have to find multiples of 7)
putting values we get,
896 = 504 +(n-1)7
392 = 7n+7
399 = 7n
n = 57
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