Math, asked by inzilrajani, 5 months ago

In square ABCD, AB= 4x-8, BC = 2x+2. Find the perimeter of the square.​

Answers

Answered by gracekumar765
5

Step-by-step explanation:

AD=BC

AB=DC

3x+2y−11=x+y+4

5x+2y+2=2x+5y−7

2x+y=15..........................eq(1) multiplied by 3

3x−3y=−9..............................eq(2)

on adding both equationswe get

6x+3y=45

3x−3y=−9

_____________________

9x=36

x=4

puting x=4 in eq(1)

2×4+y=15

y=7

AB=5x+2y+2

=5×4+2×7+2=20+14+2=36

BC=x+y+4

=4+7+4=15

So, perimetre =2(36+15)

=102

Area==36×15=540

Diagonal==

15

2

+36

2

=

1521

=39

so a b c points are correct.

hope you understand it bro do hardwrok all the all the best

Answered by krishnasaranb123
2

Answer:

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