Question

In square ABCD, P and Q are mid-point of AB and CD resp. If AB = 8cm and PQ and BD intersect
at o then find area of triangle​

Answer 1

Answer:

8 cm square

Step-by-step explanation:

AP is 4 as it is midpoint

Diagonal BD will pass from the midpoint of PQ

As PQ will be length of side of square due to located at midpoints

PO is 4

Area of triangle APO

=1/2*base *height

=1/2*PO*AP

1/2*4*4=8cm square

Answer 2

The area of triangle OPB=8 square cm

Step-by-step explanation:

Side of square ABCD=8cm

PQ=Side of square=8cm

AP=BP=$\frac{1}{2}AB=\frac{1}{2}(8)=4cm$

CQ=QD=4cm

APQD is a rectangle because pair of opposite sides are equal.

O is the mid-point of side PQ

PQ=AD

$OP=\frac{1}{2}AD=\frac{1}{2}(8)=4cm$

Area of triangle OPB=$\frac{1}{2}\times PB\times OP$

By using the formula

Area of triangle =$\frac{1}{2}\times base\times height$

Area of triangle OPB=$\frac{1}{2}\times 4\times 4=8cm^2$

Hence, the area of triangle OPB=8 square cm

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