In Square PQRS: If PQ=(3x-7) and QR=(x+3), Find PS
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Answered by
65
As it is a Square :
So,
*All the sides are equal ...
So,
3x-7=x+3
3x-x=7+3
2x=10
x=10/2
=>x = 5
Substituting:
x+3 = 5+3 = 8
PS = 8
So,
*All the sides are equal ...
So,
3x-7=x+3
3x-x=7+3
2x=10
x=10/2
=>x = 5
Substituting:
x+3 = 5+3 = 8
PS = 8
Answered by
19
Step-by-step explanation:
all sides are equal
so,
3x-7=X+3
3x-x=3+7
2x=10
X=5
substitute,
3x-7=3*5-7=15-7=8
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