Question

In stationary waves, distance between a node and its nearest antinode is 20 cm. The
phase difference between two particles having a separation of 60 cm will be
A) 7/2
L6131/2
B) zero
D) π​

Answer 1

Explanation:

Given that:

4/λ =20⇒λ=80cm, also, △ϕ= λ/2λ .△x

⇒△ϕ= 60÷80 ×2π =3π/2