In stp the no. of molecules present in 11.2 L NH3 gas is?
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Answered by
6
mole = given volume /22.4 L
=11.2 L /22.4 L = 0.5
also ,
no of molecules = mole x avogadro constant
no of molecules = 0.5 x 6.023 x 10^23
=3.0115 x 10^23
=11.2 L /22.4 L = 0.5
also ,
no of molecules = mole x avogadro constant
no of molecules = 0.5 x 6.023 x 10^23
=3.0115 x 10^23
Answered by
1
At STP ,ie in 22.4 litres of NH3 ,no of molecules present=6.023×10^23
Therefore in 11.2 litres of NH3 ,no of molecules present=(6.023×10^23 ×11.2) / 22.4
==> 3.0115×10^23 molecules
Therefore in 11.2 litres of NH3 ,no of molecules present=(6.023×10^23 ×11.2) / 22.4
==> 3.0115×10^23 molecules
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