Question

in ten rotations of screw, distance travelled on main scale is 20mm. if number of divisions on circular scale are 50 . find L.C. of micrometer screw gauge

Answer 1

Distance travelled in 10 rotations = 20 mm
Distance travelled in 1 rotation = 20/10 mm = 2 mm
Number of divisions on circular scale = 50
Pitch of screw = Distance travelled in one rotation = 2 mm

Least Count = Pitch/No. of divisions on circular scale

L.C. = 2/50 = 1/25 = 0.004 mm

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