In terms of Rydberg constant R, the shortest wavelength in Balmer series of hydrogen atom spectrum will
have wavelength
(A) IR
(B) 4/R
(C) 3/2R
(D) 9/R
ing spectral series falls within the visible range of electromagnetic radiation?
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Answer:
for shortest wavelength
n1=2
n2=∞
λ1=R(221−0)
λ=4/R
Explanation:
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