Chemistry, asked by Aditya625, 5 months ago

In tetracyanoethylene C2(CN)4, number of sp hybridized carbon atoms are X1, number of bonds are X2, number of pie bonds are X3 and number of lone pair of electrons are X4. Find out value of X1+X2+X3+X4.

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Answers

Answered by Rameshjangid

Answer: 26

Given: $C_{2} (CN)_{4}$

To find: $X_{1} +X_{2}+ X_{3} +X_{4}$

Solution:

The structural formula of $C_{2} (CN)_{4}$ ,

In the structural formula,

sp hybridised carbon = 4

σ bond = 9

π bond = 9

Lone pair = 4

So,

$X_{1} +X_{2}+ X_{3} +X_{4}$ = 4 + 9 + 9 + 4

= 26

Important definitions:

Hybridization: Energy redistribution from single-atom orbitals to equal-energy orbitals occurs when two atomic orbitals combine in a molecule to form a hybrid orbital. This process is called hybridization. In the hybridization process, atomic orbitals of comparable energy are mixed, most often the merger of two 's' orbitals or two 'p' orbitals, or 's' and 'p' and 's' orbitals. and 'd' orbitals. New orbitals created in this way are called hybrid orbitals. More importantly, hybrid orbitals are very useful in describing atomic bonding properties and molecular structures.