Question

In the above circuit find current i​

Answer 1

Answer:

Kirchoff's voltage law in loop 1 :

−2+2+(i

1

−i

2

)1=0

⇒i

1

−i

2

=0 or i

1

=i

2

---(1)

Kirchoff's Voltage law in loop 2 :

−2+(i

2

−i

1

)1+2+(i

2

−i

3

)1=0

⇒i

2

−i

3

=0 or i

2

=i

3

---(2)

Kirchoff's Voltage law in loop 3 :

−2+(i

3

−i

2

)1+2+(i

3

−i

1

)1=0

⇒i

3

=0

From (2) we get i

2

=i

3

=0

From (1) we get i

1

=i

2

=0

⇒i

1

=i

2

=i

3

=0

Answer 2

Explanation:

clock wise use

-2+2+(i

2