in the above fig AB=AC and angle ABC=50degree then find angle BOC and angle BDC
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in triangle ABC
AB=AC(GIVEN)
angle ABC=50degree
so, angle ABC=angle ACB=50degree
so,angle ( ABC+ ACB+ CAB=180)
50+50+CAB=180
CAB=180-100
CAB=80
Hence,angle ACB is 50 degree and angle CAB is 80 degree
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