Question

In the above figure,
AB = 5cm
CD = 2cm then,
(AT. DT)/(BT. CT) = ?​

Answer 1

Answer:

In given figure O is the center of circle .And lenth AB=5 cm and ∠AOB=∠COD=55

0

In ΔAOB and ΔCOD

∠AOB=∠COD=55

0

(Given )

OA=OD (Radius)

OB=OC (Radius)

∴ΔAOB≅ΔCOD

∴AB=CD=5cm Given AB=5 cm

So CD=5 cm