Question

in the above figure quadrilateral excellent is a rectangle l m equal to 21 CM XL goes to 10.5 CM diameter of the smaller semicircle is half the diameter of largest semi circle find the area of non scheduled area by brainly .com​

Answer 1

Answer:

Step-by-step explanation:

124.25 cm²

Answer 2

Answer:

124.25 cm²

Step-by-step explanation:

Let the diameter of the small semicircle be x then the diameter of the larger semicircle will be 2x.

Now from the diagram the sum of the diameters equal to the length of the rectangle.

x + 2x = 21

3x = 21

x = 7 cm

The diameters are as follows :

Small semicircle = 7 cm

Large semicircle = 14 cm

Area of a semicircle = 1/2 × pie × r²

Small semicircle = 0.5 × (7/2)² × 22/7

= 19.25 cm²

Large semicircle = 0.5 × (14/2)² × 22/7 = 77 cm²

Area of the rectangle = length × Width = 21 × 10.5 = 220.5 cm²

Total area o the shaded part = 77 + 19.5 = 96.25

Area of the non - shaded part = 220.5 - 96.25 = 124.25 cm²