in the adjacent figure ABC is a triangle in which<b=50° and <c=70° sides AB and AC are produced. if 'z' is the measure of the angle between the bisector of the exterior angles so formed, then find 'z'
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Answer:
AB is straight line
x+x+50=180
2x+50=180
2x=130
x=65
Also y+y+70=180
2y=110
y=55
Now in ΔBCD
65+55+z=180
⇒z=180−120
z=60
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