Question

I'm sorry for my previous blur question....

pl FACTORISE this....​

Answer 1

Answer:

use the formula -a²-b²=(a+b)×(a+b )

Step-by-step explanation:

please mark it as brainlist

Answer 2

Answer:

(3x - 1/6)(x + 5/6)

Step-by-step explanation:

We can use the identity of a² - b² = (a + b)(a - b).

=> (2x + 1/3)² - (x - 1/2)² = a² - b²

Comparing, a = (2x + 1/3) and b = (x - 1/2).

=> (a + b)(a - b)

=> (2x + 1/3 + x - 1/2)(2x + 1/3 - {x - 1/2})

=> (3x - 1/6)(2x + 1/3 - x + 1/2)      [Minus and plus combine to become minus]

=> (3x - 1/6)(x + 5/6) is the factorization of (2x + 1/3)² - (x - 1/2)².

If you want to open it, it will become:

=> (3x - 1/6)(x + 5/6)

=> 3x(x) + 3x(5/6) - 1/6(x) - 1/6(5/6)

=> 3x² + 5x/2 - x/6 - 5/36

=> 3x² + (15x - x/6) - 5/36

=> 3x² + 14x/6 - 5/36

=> 3x² + 7x/3 - 5/36 is the expansion of (3x - 1/6)(x + 5/6).