Question

In the adjacent figure,

AC = 6 cm, AB = 5

cm and ÐBAC =

30º. Find the area of

the triangle.​

Answer 1

Answer

cos30 ∘  =  5x

​x=  5/2cm

y=$\sqrt{5^{2} -2.5$=4.33cm

Area =  1/2×4.33×6≈13$cm^{2}$

Answer 2

Step-by-step explanation:

we know, $area = \frac{1}{2} bc \sin(A)$

here, b=6, c=5 and sinA=sin30°=1/2

substituting the values we get,

$area = \frac{1}{2} \times 6 \times 5 \times \frac{1}{2} \\ area = \frac{1}{4} \times 30 \\ area = 7.5 {unit}^{2}$

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