In the adjacent figure, angleCAB || angleBAD = 1 : 2 Find the alternet internal angles of triangle ABC.
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Step-by-step explanation:
∠DAB=∠ABC=x(Alternate angles)
∠ABC+∠BCA=∠BAE(Sum of interior remote angles of a ∆ is equal to the exterior angle)
x+x+13=69+x
x+x-x=69-13
x=56°
1st ∠=x=56°
2nd ∠=x+13=56+13=69°
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