Question

In the adjacent figure
EFG is a right triangle
EF = 5cm & EG = 13cm
Find 1) Length of FG
2) Ar. ( . EFG)
​

Answer 1

the length if FG is 12 cm

area = 1/2 * 12* 5

= 30 sq. cm

Answer 2

Answer:

FG = 12 cm , Area = 30 sq. cm

Step-by-step explanation:

EF = 5 cm

EG = 13 cm

By Pythagoras Theorem ,

FG × FG = EG × EG - EF × EF

= 13 × 13 - 5 × 5

= 169 - 25

= 144

=> FG = 12 cm

Area = 1/2 × EF × FG

= 1/2 × 5 × 12

= 30 sq. cm

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