Question

in the adjacent figure ,it is given that AB=AC,angle BAC=36°,angle ADB =45°,find
(i) angle ABC

(ii) angle ACB

(iii) angle DAB

(iv) angle EAC​

Answer 1

Answer:

In △ABC

AB=AC

So △ABC is isoceles.

⇒∠ABC=∠ACB

∠BAC+∠ABC+∠ACB=180∘ (Angle sum property of triangle)

36∘ +∠ACB+∠ACB=180∘

2∠ACB=180∘ −36∘

2∠ACB=144∘

∠ACB= 144 / 2∘

=72∘

Hope this is helpful for you.