in the adjacent figure it is given that AB equals to AC angle BAC equal to 36 degrees angle ADB equals to 45 degrees and Angle a is equals to 40 degrees find angle abc angle ACB angle dab angle EAC
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in triangle ABC
AB=BC
angle B=angle C
sum of 3 angles in a triangle =180°
36°+x+x=180
36+2x=180
2x=180- 36
2x=144
x=72°
angleABC=72°
angle ACB=72°
angle ACB+angle ACE=180°(Straight line)
72+x=180
x=180- 72
x=108°
angleAEC=108°
from triangle ACE
sum of 3 angles =180°
40+108+x=180
148+x=180
x=180-148
x=32°
angle EAC=32°
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