Question

in the adjacent figure it is given thatAB=AC,

Answer 1

Given, AB = AC
<BAC=36°, <ADB=45°,<AEC=40°

(i) <ABC+<ACB+<BAC=180°
=><ABC+<ABC+36°=180°( Since, AB=AC, there opposite two angles are equal..which is an isosceles triangle)
=>2<ABC+36°=180°
=>2<ABC=180° - 36° =144°
=><ABC=144/2 =72°
(ii) Since, <ABC=<ACB [ From question (i) ]
<ACB=72°
(iii) In ∆ ABD we have,
<ABC=<DAB+<ADB ( Since exterior angle = sum of two opposite interior angle)
=>72°=<DAB+45°
=>72° - 45°=<DAB
=>27°=<DAB
(iv)In ∆ EAC we have,
=><ACB=<CAE+<AEC (Since exterior angle = sum of two opposite interior angle)
=>72°=<CAE+40°
=>72° - 40°=<CAE
=>32°=<CAE
IF YOU LIKE IT PLEASE MARK IT BRAINLIEST

Answer 2

Answer:

Hiiiiiiiiiii

I hope to help you